Consider the following situation. Let us be: 1/4> 1/8 but this same inequality can be written in another way where the inequality sign will be the same: (1/2) 2> (1/2) 3 Applying the logarithms on both members and Since the logarithm is a growing function, that is, a larger number corresponds to a larger logarithm, we will have: log ((1/2) 2)> log ((1/2) 3), so by the properties of the logarithms we have: 2 .
Come here my brother Learn how to do The true way The whole number potentiation Come here, come here my friend my brother Come find out with me The secret of learning empowerment If the exponent is even my brother stay active the power will always give a positive number Come on here, come here ... If the exponent is odd pay attention at this stage the power will always have the same signal as the base Come here, come here ... In the multiplication of equal base powers my brother be aware you repeat the base and add the exponents Come here , come here ... And in the room?
A special symbol We have to find out what the rule of this operation is. Note that: 2 4 = 10 = 2 x 4 + 2 3 8 = 27 = 3 x 8 + 3, 4 27 = 112 = 4 x 27 + 4 5 1 = 10 = 5 x 1 + 5 We can conclude that the rule that defines the operation is ab = axb + a. Thus we have: 4 (8 7) = 4 (8 x 7 + 8) = 4 64 = 4 x 64 + 4 = 260. Back to statement Challenge 157 The multiple of 9 Challenge index Next >> Challenge 159 bus
Being MATH is… Solving Your Problems Ending All COMPLEXES Knowing Your FUNCTION AND BEING DETERMINANT Overcoming Your Limit Whatever the Variable or Its Derivative But Always Having the Reason Not Being an INDEPENDENT TERM Always Being Together In Search of a Solution . Carla Patricia de Oliveira Passionate Mathematician Poems Index Next >> Mathematics Sonnet
How many pages does the book have? Since N is the number of pages in the book, we have: N / 5 = (N / 3) -16 (N / 5) - (N / 3) = -16 (3N-5N) / 15 = -16 3N-5N = -16 * 15 -2N = -240 N = 120 The book has 120 pages! Back to statement Challenge 9 Ducks and dogs Challenge table of contents Next >> Challenge 11 Find the values of x, y and z