## Which fits you best?

Observe this diagram:

Considering that the radius of the circle is *r*, then the area of the circle is given by πr^{2} and the area of the outer square will be (2r)^{2} = 4r^{2}.

We also realize that the blue square is exactly half the area of the outer square, so its area will be 2r^{2}. We have then:

(Circle Area) / (Outer Square Area) = πr^{2} / 4r^{2} = π / 4, which is worth approximately 78.5%.

(Small square area) / (Circle area) = 2r^{2} / πr^{2} = 2 / π, which is worth approximately 63.7%.

Therefore, in the first case the piece fits better, as it occupies a larger area (78.5%).

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