## Solve the equation

By the definition of logarithm, we can write:

**log _{y} 0.001 = 2 - log y**

From log base change rule_{B} a = (log a) / (log b), come:

**(log 0.001) / (log y) = 2 - log y**

We know that log 0.001 = -3, so:

**-3 / (log y) = 2 - log y**

**-3 = 2 log y - log ^{2} ylog^{2} y - 2 log y - 3 = 0 (2nd degree equation)**

**Applying Bhaskara's formula we find:**

**log y = 3 or log y = -1 y = 1000 or y = 0.1**

**Solution Set = {1000; 0.1}**

**Back to statement**